Function F F F Is Defined By F ( X ) = − A X + B F(x) = -a^x + B F ( X ) = − A X + B , Where A A A And B B B Are Constants. In The X Y Xy X Y -plane, The Graph Of Y = F ( X ) − 15 Y = F(x) - 15 Y = F ( X ) − 15 Has A Y Y Y -intercept At $\left(0,

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Introduction

In mathematics, functions are used to describe the relationship between variables. A function ff is defined by f(x)=ax+bf(x) = -a^x + b, where aa and bb are constants. In this article, we will analyze the graph of y=f(x)15y = f(x) - 15 and determine the yy-intercept.

The Graph of y=f(x)15y = f(x) - 15

The graph of y=f(x)15y = f(x) - 15 is obtained by shifting the graph of y=f(x)y = f(x) down by 15 units. This means that for every point (x,y)(x, y) on the graph of y=f(x)y = f(x), the corresponding point on the graph of y=f(x)15y = f(x) - 15 is (x,y15)(x, y - 15).

The yy-Intercept

The yy-intercept of a graph is the point where the graph intersects the yy-axis. In other words, it is the point where x=0x = 0. To find the yy-intercept of the graph of y=f(x)15y = f(x) - 15, we need to find the value of yy when x=0x = 0.

Finding the yy-Intercept

Let's substitute x=0x = 0 into the equation y=f(x)15y = f(x) - 15. We get:

y=f(0)15y = f(0) - 15

Since f(x)=ax+bf(x) = -a^x + b, we have:

f(0)=a0+bf(0) = -a^0 + b

Recall that a0=1a^0 = 1 for any nonzero number aa. Therefore, we have:

f(0)=1+bf(0) = -1 + b

Substituting this into the equation for yy, we get:

y=(1+b)15y = (-1 + b) - 15

Simplifying, we get:

y=16+by = -16 + b

Conclusion

In conclusion, the graph of y=f(x)15y = f(x) - 15 has a yy-intercept at (0,16+b)\left(0, -16 + b\right). This means that the graph intersects the yy-axis at the point (0,16+b)\left(0, -16 + b\right).

Properties of the Graph

The graph of y=f(x)15y = f(x) - 15 has several properties that are worth noting:

  • The graph is a downward-opening parabola.
  • The vertex of the parabola is at the point (0,16+b)\left(0, -16 + b\right).
  • The graph intersects the xx-axis at the point (x,0)\left(x, 0\right), where xx is a solution to the equation ax+b=15-a^x + b = 15.

Solving the Equation

To find the solution to the equation ax+b=15-a^x + b = 15, we can rearrange the equation to get:

ax=15b-a^x = 15 - b

Dividing both sides by 1-1, we get:

ax=b15a^x = b - 15

Taking the logarithm of both sides, we get:

xloga=log(b15)x \log a = \log (b - 15)

Dividing both sides by loga\log a, we get:

x=log(b15)logax = \frac{\log (b - 15)}{\log a}

This is the solution to the equation ax+b=15-a^x + b = 15.

Graphing the Function

To graph the function y=f(x)15y = f(x) - 15, we can use a graphing calculator or a computer algebra system. We can also use a table of values to plot the graph.

Table of Values

Here is a table of values for the function y=f(x)15y = f(x) - 15:

xx yy
0 -16 + b
1 -a + b - 15
2 a^2 - b - 15
3 -a^3 + b - 15
... ...

Graphing the Function

Using a graphing calculator or a computer algebra system, we can plot the graph of y=f(x)15y = f(x) - 15. The graph will be a downward-opening parabola with a vertex at the point (0,16+b)\left(0, -16 + b\right).

Conclusion

Q: What is the yy-intercept of the graph of y=f(x)15y = f(x) - 15?

A: The yy-intercept of the graph of y=f(x)15y = f(x) - 15 is the point where the graph intersects the yy-axis. In other words, it is the point where x=0x = 0. To find the yy-intercept, we need to find the value of yy when x=0x = 0. We get:

y=f(0)15y = f(0) - 15

Since f(x)=ax+bf(x) = -a^x + b, we have:

f(0)=a0+bf(0) = -a^0 + b

Recall that a0=1a^0 = 1 for any nonzero number aa. Therefore, we have:

f(0)=1+bf(0) = -1 + b

Substituting this into the equation for yy, we get:

y=(1+b)15y = (-1 + b) - 15

Simplifying, we get:

y=16+by = -16 + b

So, the yy-intercept of the graph of y=f(x)15y = f(x) - 15 is (0,16+b)\left(0, -16 + b\right).

Q: What is the vertex of the graph of y=f(x)15y = f(x) - 15?

A: The vertex of the graph of y=f(x)15y = f(x) - 15 is the point where the graph changes from concave up to concave down. To find the vertex, we need to find the value of xx that makes the derivative of the function equal to zero. The derivative of the function f(x)=ax+bf(x) = -a^x + b is:

f(x)=axlogaf'(x) = -a^x \log a

Setting the derivative equal to zero, we get:

axloga=0-a^x \log a = 0

Since axa^x is never equal to zero, we can divide both sides by ax-a^x to get:

loga=0\log a = 0

This is a contradiction, since loga\log a is never equal to zero. Therefore, the graph of y=f(x)15y = f(x) - 15 has no vertex.

Q: How do I graph the function y=f(x)15y = f(x) - 15?

A: To graph the function y=f(x)15y = f(x) - 15, you can use a graphing calculator or a computer algebra system. You can also use a table of values to plot the graph.

Here is a table of values for the function y=f(x)15y = f(x) - 15:

xx yy
0 -16 + b
1 -a + b - 15
2 a^2 - b - 15
3 -a^3 + b - 15
... ...

Using a graphing calculator or a computer algebra system, you can plot the graph of y=f(x)15y = f(x) - 15. The graph will be a downward-opening parabola with a vertex at the point (0,16+b)\left(0, -16 + b\right).

Q: What is the solution to the equation ax+b=15-a^x + b = 15?

A: To find the solution to the equation ax+b=15-a^x + b = 15, we can rearrange the equation to get:

ax=15b-a^x = 15 - b

Dividing both sides by 1-1, we get:

ax=b15a^x = b - 15

Taking the logarithm of both sides, we get:

xloga=log(b15)x \log a = \log (b - 15)

Dividing both sides by loga\log a, we get:

x=log(b15)logax = \frac{\log (b - 15)}{\log a}

This is the solution to the equation ax+b=15-a^x + b = 15.

Q: What is the relationship between the graph of y=f(x)15y = f(x) - 15 and the graph of y=f(x)y = f(x)?

A: The graph of y=f(x)15y = f(x) - 15 is obtained by shifting the graph of y=f(x)y = f(x) down by 15 units. This means that for every point (x,y)(x, y) on the graph of y=f(x)y = f(x), the corresponding point on the graph of y=f(x)15y = f(x) - 15 is (x,y15)(x, y - 15).

Q: What is the significance of the yy-intercept of the graph of y=f(x)15y = f(x) - 15?

A: The yy-intercept of the graph of y=f(x)15y = f(x) - 15 is the point where the graph intersects the yy-axis. This point is significant because it represents the value of the function when x=0x = 0. In other words, it represents the value of the function at the origin.

Q: How do I determine the values of aa and bb in the function f(x)=ax+bf(x) = -a^x + b?

A: To determine the values of aa and bb in the function f(x)=ax+bf(x) = -a^x + b, you need to have additional information about the function. For example, you may know the value of the function at a particular point, or you may know the derivative of the function at a particular point. Using this information, you can solve for the values of aa and bb.

Conclusion

In conclusion, the graph of y=f(x)15y = f(x) - 15 has a yy-intercept at (0,16+b)\left(0, -16 + b\right). The graph is a downward-opening parabola with a vertex at the point (0,16+b)\left(0, -16 + b\right). The graph intersects the xx-axis at the point (x,0)\left(x, 0\right), where xx is a solution to the equation ax+b=15-a^x + b = 15.