What Mass Of Sodium Chloride ( N A C L NaCl N A Cl ) Forms When 7.5 G Of Sodium Carbonate ( N A 2 C O 3 Na_2CO_3 N A 2 ​ C O 3 ​ ) Reacts With A Dilute Solution Of Hydrochloric Acid ( H C L HCl H Cl )? Type In Your Answer Using The Correct Number Of Significant Figures.Reaction:

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Introduction

In this article, we will explore the chemical reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) to form sodium chloride ($NaCl$) and carbon dioxide ($CO_2$). The reaction is as follows:

$$Na_2CO_3 + 2HCl \rightarrow 2NaCl + H_2O + CO_2$$

Reaction Stoichiometry

To determine the mass of sodium chloride ($NaCl$) formed, we need to understand the stoichiometry of the reaction. The balanced equation shows that 1 mole of sodium carbonate ($Na_2CO_3$) reacts with 2 moles of hydrochloric acid ($HCl$) to produce 2 moles of sodium chloride ($NaCl$).

Molar Mass Calculations

To calculate the mass of sodium chloride ($NaCl$) formed, we need to know the molar masses of the reactants and products. The molar masses are as follows:

• Sodium carbonate ($Na_2CO_3$): 105.99 g/mol
• Hydrochloric acid ($HCl$): 36.46 g/mol
• Sodium chloride ($NaCl$): 58.44 g/mol
• Carbon dioxide ($CO_2$): 44.01 g/mol

Limiting Reactant

To determine the limiting reactant, we need to calculate the number of moles of sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) present.

Number of moles of sodium carbonate ($Na_2CO_3$) = mass of sodium carbonate ($Na_2CO_3$) / molar mass of sodium carbonate ($Na_2CO_3$) = 7.5 g / 105.99 g/mol = 0.0707 mol

Number of moles of hydrochloric acid ($HCl$) = mass of hydrochloric acid ($HCl$) / molar mass of hydrochloric acid ($HCl$) = 2 x 0.0707 mol (since 2 moles of $HCl$ are required to react with 1 mole of $Na_2CO_3$) = 0.1414 mol

Since the number of moles of hydrochloric acid ($HCl$) is greater than the number of moles of sodium carbonate ($Na_2CO_3$), sodium carbonate ($Na_2CO_3$) is the limiting reactant.

Mass of Sodium Chloride ($NaCl$) Formed

Now that we know the limiting reactant, we can calculate the mass of sodium chloride ($NaCl$) formed.

Number of moles of sodium chloride ($NaCl$) formed = 2 x number of moles of sodium carbonate ($Na_2CO_3$) = 2 x 0.0707 mol = 0.1414 mol

Mass of sodium chloride ($NaCl$) formed = number of moles of sodium chloride ($NaCl$) formed x molar mass of sodium chloride ($NaCl$) = 0.1414 mol x 58.44 g/mol = 8.24 g

Conclusion

In this article, we have explored the chemical reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) to form sodium chloride ($NaCl$) and carbon dioxide ($CO_2$). We have calculated the mass of sodium chloride ($NaCl$) formed using the stoichiometry of the reaction and the molar masses of the reactants and products. The mass of sodium chloride ($NaCl$) formed is 8.24 g.

Discussion

The reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) is a common laboratory experiment used to demonstrate the principles of chemical reactions and stoichiometry. The reaction is also used in various industrial applications, such as the production of sodium chloride ($NaCl$) and carbon dioxide ($CO_2$).

Limitations

One limitation of this article is that it assumes a dilute solution of hydrochloric acid ($HCl$). In reality, the concentration of hydrochloric acid ($HCl$) can affect the rate of reaction and the yield of sodium chloride ($NaCl$). Additionally, the article assumes that the reaction is carried out in a controlled environment, such as a laboratory. In real-world applications, the reaction may be affected by various factors, such as temperature, pressure, and the presence of impurities.

Future Work

Future work could involve investigating the effects of different concentrations of hydrochloric acid ($HCl$) on the rate of reaction and the yield of sodium chloride ($NaCl$). Additionally, the reaction could be carried out in a more realistic environment, such as a industrial setting, to investigate the effects of temperature, pressure, and impurities on the reaction.

References

• [1] "Chemical Reactions and Stoichiometry" by OpenStax
• [2] "Sodium Carbonate" by Wikipedia
• [3] "Hydrochloric Acid" by Wikipedia
• [4] "Sodium Chloride" by Wikipedia

Acknowledgments

The author would like to acknowledge the support of [Name] for this article.

Introduction

In our previous article, we explored the chemical reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) to form sodium chloride ($NaCl$) and carbon dioxide ($CO_2$). In this article, we will answer some frequently asked questions about this reaction.

Q: What is the balanced equation for the reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$)?

A: The balanced equation for the reaction is:

$$Na_2CO_3 + 2HCl \rightarrow 2NaCl + H_2O + CO_2$$

Q: What is the limiting reactant in this reaction?

A: The limiting reactant is sodium carbonate ($Na_2CO_3$). This means that the amount of sodium carbonate ($Na_2CO_3$) present is less than the amount of hydrochloric acid ($HCl$) required to react with it.

Q: How do you calculate the mass of sodium chloride ($NaCl$) formed in this reaction?

A: To calculate the mass of sodium chloride ($NaCl$) formed, you need to know the number of moles of sodium carbonate ($Na_2CO_3$) present and the molar mass of sodium chloride ($NaCl$). The number of moles of sodium chloride ($NaCl$) formed is twice the number of moles of sodium carbonate ($Na_2CO_3$) present. The mass of sodium chloride ($NaCl$) formed is then calculated by multiplying the number of moles of sodium chloride ($NaCl$) formed by its molar mass.

Q: What is the molar mass of sodium chloride ($NaCl$)?

A: The molar mass of sodium chloride ($NaCl$) is 58.44 g/mol.

Q: What is the molar mass of sodium carbonate ($Na_2CO_3$)?

A: The molar mass of sodium carbonate ($Na_2CO_3$) is 105.99 g/mol.

Q: What is the molar mass of hydrochloric acid ($HCl$)?

A: The molar mass of hydrochloric acid ($HCl$) is 36.46 g/mol.

Q: What is the molar mass of carbon dioxide ($CO_2$)?

A: The molar mass of carbon dioxide ($CO_2$) is 44.01 g/mol.

Q: What is the purpose of this reaction in industrial applications?

A: The reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$) is used in various industrial applications, such as the production of sodium chloride ($NaCl$) and carbon dioxide ($CO_2$).

Q: What are some common laboratory experiments that use this reaction?

A: This reaction is commonly used in laboratory experiments to demonstrate the principles of chemical reactions and stoichiometry.

Q: What are some limitations of this reaction?

A: One limitation of this reaction is that it assumes a dilute solution of hydrochloric acid ($HCl$). In reality, the concentration of hydrochloric acid ($HCl$) can affect the rate of reaction and the yield of sodium chloride ($NaCl$). Additionally, the reaction may be affected by various factors, such as temperature, pressure, and the presence of impurities.

Q: What are some future directions for research on this reaction?

A: Future work could involve investigating the effects of different concentrations of hydrochloric acid ($HCl$) on the rate of reaction and the yield of sodium chloride ($NaCl$). Additionally, the reaction could be carried out in a more realistic environment, such as an industrial setting, to investigate the effects of temperature, pressure, and impurities on the reaction.

Q: What are some common mistakes to avoid when performing this reaction?

A: Some common mistakes to avoid when performing this reaction include:

• Not using a dilute solution of hydrochloric acid ($HCl$)
• Not controlling the temperature and pressure of the reaction
• Not using a suitable container for the reaction
• Not wearing protective gear, such as gloves and goggles

Q: What are some safety precautions to take when performing this reaction?

A: Some safety precautions to take when performing this reaction include:

• Wearing protective gear, such as gloves and goggles
• Using a suitable container for the reaction
• Controlling the temperature and pressure of the reaction
• Not ingesting or inhaling any chemicals used in the reaction

Conclusion

In this article, we have answered some frequently asked questions about the reaction between sodium carbonate ($Na_2CO_3$) and hydrochloric acid ($HCl$). We hope that this article has provided useful information and insights for those interested in this reaction.