Which Is Equivalent To $\sqrt[5]{1,215}^x$?A. $243^x$B. $1,215^{\frac{1}{5} X}$C. $1,215^{\frac{1}{5x}}$D. $243^{\frac{1}{x}}$

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Introduction

In mathematics, simplifying exponential expressions is a crucial skill that helps us to manipulate and solve complex equations. One of the key concepts in this area is the ability to rewrite expressions in equivalent forms. In this article, we will explore how to simplify the expression 1,2155x\sqrt[5]{1,215}^x and find its equivalent form.

Understanding the Expression

The given expression is 1,2155x\sqrt[5]{1,215}^x. To simplify this expression, we need to understand the properties of exponents and radicals. The expression can be rewritten as (1,215)15x(1,215)^{\frac{1}{5}x} using the property of radicals that an=a1n\sqrt[n]{a} = a^{\frac{1}{n}}. This is a fundamental concept in mathematics that helps us to simplify expressions involving radicals.

Simplifying the Expression

Now that we have rewritten the expression as (1,215)15x(1,215)^{\frac{1}{5}x}, we can simplify it further. To do this, we need to find the prime factorization of 1,215. The prime factorization of 1,215 is 35β‹…5β‹…73^5 \cdot 5 \cdot 7. Using this factorization, we can rewrite the expression as (35β‹…5β‹…7)15x(3^5 \cdot 5 \cdot 7)^{\frac{1}{5}x}.

Using the Property of Exponents

Now that we have rewritten the expression as (35β‹…5β‹…7)15x(3^5 \cdot 5 \cdot 7)^{\frac{1}{5}x}, we can use the property of exponents that (am)n=amn(a^m)^n = a^{mn} to simplify it further. Applying this property, we get 35β‹…15xβ‹…515xβ‹…715x3^{5 \cdot \frac{1}{5}x} \cdot 5^{\frac{1}{5}x} \cdot 7^{\frac{1}{5}x}.

Simplifying the Expression Further

Now that we have simplified the expression to 3xβ‹…515xβ‹…715x3^{x} \cdot 5^{\frac{1}{5}x} \cdot 7^{\frac{1}{5}x}, we can see that it is equivalent to 3xβ‹…(5β‹…7)15x3^x \cdot (5 \cdot 7)^{\frac{1}{5}x}. Using the property of exponents that amβ‹…an=am+na^m \cdot a^n = a^{m+n}, we can simplify this expression further to 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x}.

Finding the Equivalent Form

Now that we have simplified the expression to 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x}, we can see that it is equivalent to 2431x243^{\frac{1}{x}}. To see why this is the case, we need to understand the properties of exponents and radicals. The expression 2431x243^{\frac{1}{x}} can be rewritten as (35)1x(3^5)^{\frac{1}{x}} using the property of exponents that (am)n=amn(a^m)^n = a^{mn}. This is equivalent to 35β‹…1x3^{5 \cdot \frac{1}{x}}, which is the same as 35x3^{\frac{5}{x}}.

Conclusion

In conclusion, the expression 1,2155x\sqrt[5]{1,215}^x is equivalent to 2431x243^{\frac{1}{x}}. This is because we can rewrite the expression as (1,215)15x(1,215)^{\frac{1}{5}x} using the property of radicals that an=a1n\sqrt[n]{a} = a^{\frac{1}{n}}. We can then simplify this expression further using the property of exponents that (am)n=amn(a^m)^n = a^{mn}. Finally, we can see that the expression is equivalent to 2431x243^{\frac{1}{x}} by understanding the properties of exponents and radicals.

Answer

Q: What is the property of radicals that helps us to simplify expressions involving radicals?

A: The property of radicals that helps us to simplify expressions involving radicals is an=a1n\sqrt[n]{a} = a^{\frac{1}{n}}. This property allows us to rewrite expressions involving radicals in terms of exponents.

Q: How do we simplify the expression 1,2155x\sqrt[5]{1,215}^x?

A: To simplify the expression 1,2155x\sqrt[5]{1,215}^x, we need to understand the properties of exponents and radicals. We can rewrite the expression as (1,215)15x(1,215)^{\frac{1}{5}x} using the property of radicals that an=a1n\sqrt[n]{a} = a^{\frac{1}{n}}. We can then simplify this expression further using the property of exponents that (am)n=amn(a^m)^n = a^{mn}.

Q: What is the prime factorization of 1,215?

A: The prime factorization of 1,215 is 35β‹…5β‹…73^5 \cdot 5 \cdot 7.

Q: How do we use the property of exponents to simplify the expression (35β‹…5β‹…7)15x(3^5 \cdot 5 \cdot 7)^{\frac{1}{5}x}?

A: We can use the property of exponents that (am)n=amn(a^m)^n = a^{mn} to simplify the expression (35β‹…5β‹…7)15x(3^5 \cdot 5 \cdot 7)^{\frac{1}{5}x}. This gives us 35β‹…15xβ‹…515xβ‹…715x3^{5 \cdot \frac{1}{5}x} \cdot 5^{\frac{1}{5}x} \cdot 7^{\frac{1}{5}x}.

Q: How do we simplify the expression 3xβ‹…515xβ‹…715x3^{x} \cdot 5^{\frac{1}{5}x} \cdot 7^{\frac{1}{5}x} further?

A: We can simplify the expression 3xβ‹…515xβ‹…715x3^{x} \cdot 5^{\frac{1}{5}x} \cdot 7^{\frac{1}{5}x} further by using the property of exponents that amβ‹…an=am+na^m \cdot a^n = a^{m+n}. This gives us 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x}.

Q: How do we find the equivalent form of the expression 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x}?

A: We can find the equivalent form of the expression 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x} by understanding the properties of exponents and radicals. The expression 3xβ‹…3515x3^x \cdot 35^{\frac{1}{5}x} is equivalent to 2431x243^{\frac{1}{x}}.

Q: What is the correct answer to the original question?

A: The correct answer to the original question is B. 1,21515x1,215^{\frac{1}{5} x}.

Q: Why is the expression 1,2155x\sqrt[5]{1,215}^x equivalent to 2431x243^{\frac{1}{x}}?

A: The expression 1,2155x\sqrt[5]{1,215}^x is equivalent to 2431x243^{\frac{1}{x}} because we can rewrite the expression as (1,215)15x(1,215)^{\frac{1}{5}x} using the property of radicals that an=a1n\sqrt[n]{a} = a^{\frac{1}{n}}. We can then simplify this expression further using the property of exponents that (am)n=amn(a^m)^n = a^{mn}. Finally, we can see that the expression is equivalent to 2431x243^{\frac{1}{x}} by understanding the properties of exponents and radicals.

Conclusion

In conclusion, simplifying exponential expressions is a crucial skill that helps us to manipulate and solve complex equations. By understanding the properties of exponents and radicals, we can rewrite expressions involving radicals in terms of exponents and simplify them further. The correct answer to the original question is B. 1,21515x1,215^{\frac{1}{5} x}.